# Mensuration Formulas in Telugu – 10th Class Maths

ఈ రోజు ఆర్టికల్ లో మనం కొన్ని Mensuration Formulas తెలుసుకోవచ్చు.

Maths లో ఫార్ములాస్ తెలుసుకోవడం చాలా ముఖ్యం.

Mensuration Formulas తెలుసుకోవడం ద్వారా మనం Mensuration లో Problems ఈజీ గా solve చేయవచ్చు.

Area of a square: A = s^2, where s is the length of one side.

Area of a rectangle: A = l × w, where l is the length and w is the width.

Area of a parallelogram: A = b × h, where b is the base and h is the height.

Area of a triangle: A = 1/2 × b × h, where b is the base and h is the height.

Area of a trapezoid: A = 1/2 × (b1 + b2) × h, where b1 and b2 are the lengths of the parallel sides and h is the height.

Circumference of a circle: C = 2πr, where r is the radius of the circle and π (pi) is a constant approximately equal to 3.14.

Area of a circle: A = πr^2, where r is the radius of the circle and π (pi) is a constant approximately equal to 3.14.

Volume of a cube: V = s^3, where s is the length of one side.

Volume of a rectangular prism: V = l × w × h, where l is the length, w is the width, and h is the height.

Volume of a cylinder: V = πr^2h, where r is the radius of the circular base, h is the height, and π (pi) is a constant approximately equal to 3.14.

Volume of a sphere: V = 4/3 × πr^3, where r is the radius of the sphere and π (pi) is a constant approximately equal to 3.14.

Surface area of a cube: A = 6s^2, where s is the length of one side.

Surface area of a rectangular prism: A = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height.

Surface area of a cylinder: A = 2πr^2 + 2πrh, where r is the radius of the circular base, h is the height, and π (pi) is a constant approximately equal to 3.14.

Surface area of a sphere: A = 4πr^2, where r is the radius of the sphere and π (pi) is a constant approximately equal to 3.14

మీకు ఈ ఆర్టికల్ హెల్ప్ అవుతాదని అనుకుంటున్నాను.

మీకు ఏమయినా సందేహాలు ఉంటే కింద కామెంట్ చేయండి.

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